Calculus Help

[Catalyst]

Anyone on here know how to do calculus, or have a enough understanding of first year calculus to help explain this to me?

The question is.....
differentiate ln(ln3x)=0

and if u can do that can u try this to

d/dt (lnt)^3


Thanks...

[andy ross]

oh gosh ben ray look what you started : )

[myers]

ok...

d/dx lnx = (1/x) x (dx/dx) which equals just 1/x

ln(ln3x) is a chain rule so....

d/dx ln(ln3x) = (1/(ln3x)) x (1/(3x)) x (3)

=================================

d/dt (lnt)^3

chain rule of x^3 so...

d/dt (lnt)^3 = 3(lnt)^2 x (1/t)

=================================

hope this helps lemme know if you have any questions or i need to write it out differently

[i<3wksk8]

yea every post up their homework. their will always be someone that can do it better than you.

[Catalyst]

myers, thanks man, for the second one i fizzle up im supposed to find the second derivative of that so is it just like..

d/dt (lnt)^3 = 3(lnt)^2 x (1/t)
= 6(lnt) x -t^-2 x (1/t)???????????

I dont think thats right but its the only thing i can think of

[integrity640]

[s34n]

get a program called "MAPLE"

It's genious really, if I knew about it in high school i would have be very pleased. I think you can even download it via torrents from torrentspy.com

Great with graphing, derivatives, etc. For first year engineering where I'm at it is mandatory to have, because its so convenient for calculus. If you need any help with it, let me know. I HIGHLY recommend it t anyone taking calculus.

[Greg T]

I dont even get to use a calculator in my calc classes

[Jholiday]

this looks like another language

[shane]

[myers]

Catalyst, you got the right idea you just have to do the product rule becuase its a variable times a variable so...

d/dx (uv) = (deriv of u)(v) + (deriv of v)(u)

u= 3(lnt)^2
v= (1/t)

therefore:

d/dx [3(lnt)^2]x[1/t] = [(6lnt)(1/t)][1/t] + [(3(lnt)^2][-1/(t^2)]

________^u____^v_______^u'___^v__+____^v'______^u

dont pay attention to the __ thingys it just wouldnt let me space it out without them

[Greg T]

[Catalyst]

myers, thanks alot man, i think im starting to get this stuff now, the math help center opens today on campus so im going to hit that up
thanks again

[myers]

yea man no problem, once you get all the derivatives memorized it gets alot easier, kinda reminds me of factoring from algebra 1. the main things you gotta know are the chain rule, product rule, and quotient rule and you can pretty much do any of them